(2x-5)^2+3(2x-5)-4=0

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Solution for (2x-5)^2+3(2x-5)-4=0 equation: 



(2x-5)^2+3(2x-5)-4=0

We multiply parentheses

(2x-5)^2+6x-15-4=0

We add all the numbers together, and all the variables

6x+(2x-5)^2-19=0

We move all terms containing x to the left, all other terms to the right

6x+(2x-5)^2=19

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